x^2-8x^2+26=0

Solution for x^2-8x^2+26=0 equation:

x^2-8x^2+26=0

We add all the numbers together, and all the variables

-7x^2+26=0

a = -7; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-7)·26
Δ = 728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{728}=\sqrt{4*182}=\sqrt{4}*\sqrt{182}=2\sqrt{182}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{182}}{2*-7}=\frac{0-2\sqrt{182}}{-14}
=-\frac{2\sqrt{182}}{-14}
=-\frac{\sqrt{182}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{182}}{2*-7}=\frac{0+2\sqrt{182}}{-14}
=\frac{2\sqrt{182}}{-14}
=\frac{\sqrt{182}}{-7}
$